Answer:
[tex]-1.13 m/s^2[/tex]
Explanation:
The acceleration of an object is given by:
[tex]a=\frac{v-u}{t}[/tex]
where
v is the final velocity
u is the initial velocity
t is the time it takes for the velocity to change from u to v
For this problem, first we have to convert the velocities of the car from mph to m/s:
[tex]u = 65 mi/h \cdot \frac{1609 m/mi}{3600 s/h}=29.1 m/s[/tex]
[tex]v = 55 mi/h \cdot \frac{1609 m/mi}{3600 s/h}=24.6 m/s[/tex]
While the time interval is
t = 4.0 s
Substituting, we find the acceleration:
[tex]a=\frac{24.6-29.1}{4.0}=-1.13 m/s^2[/tex]
