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3.25 kg object initially moving in the positive x direction with a velocity of 5.34 m s collides with and sticks to a 1.78 kg object initially moving in the negative y direction with a velocity of 3.22 m s Find the final components of velocity of the composite object Indicate the direction with the sign of your answer

Respuesta :

Answer:

it will move in x direction with speed

[tex]v_x = 3.45 m/s[/tex]

it will move in -y direction with speed

[tex]v_y = 1.14 m/s[/tex]

Explanation:

As we know that when two objects are colliding then the net force on the system of two masses will be zero

So total momentum of the system of mass will remains conserved

[tex]m_1v_{1i} + m_2v_{2i} = (m_1 + m_2) v_f[/tex]

here we have

[tex]m_1 = 3.25 kg[/tex]

[tex]m_2 = 1.78 kg[/tex]

[tex]v_{1i} = 5.34 m/s \hat i[/tex]

[tex]v_{2i} = -3.22 \hat j[/tex]

now we will have

[tex]3.25(5.34\hat i) + 1.78(-3.22\hat j) = (3.25 + 1.78)v_f[/tex]

[tex]v_f = 3.45 \hat i - 1.14 \hat j[/tex]

so it will move in x direction with speed

[tex]v_x = 3.45 m/s[/tex]

it will move in -y direction with speed

[tex]v_y = 1.14 m/s[/tex]

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