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A crate having mass 50.0 kg falls horizontally off the back of the flatbed truck, which is traveling at 100 km/h. Find the value of the coefficient of kinetic friction between the road and crate if the crate slides 50 m on the road in coming to rest. The initial speed of the crate is the same as the truck, 100 km/h.

Respuesta :

Answer:

[tex]\mu = 0.786[/tex]

Explanation:

As we know that initial speed of the crate is

[tex]v_i = 100 km/h[/tex]

[tex]v_i = 27.78 m/s[/tex]

now finally the crate will come to rest

so we have

[tex]v_f = 0[/tex]

now the deceleration due to frictional force is given as

[tex]a = -\mu g[/tex]

distance moved by the crate before it will stop is given as

[tex]d = 50 m[/tex]

so we will have

[tex]0 - 27.78^2 = 2(-\mu(9.81))50[/tex]

[tex]\mu = 0.786[/tex]

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