Answer:
562.8 kPa
Explanation:
We can solve the problem by using Boyle's law, which states that the product between the pressure of a gas kept at constant temperature and its volume is constant:
[tex]p V = const.[/tex]
which can also be written as
[tex]p_1 V_1 = p_2 V_2[/tex]
In this problem:
[tex]p_1 = 101.3 kPa[/tex] is the initial pressure of the gas
[tex]V_1 = 25.0 L[/tex] is the initial volume
Later, the gas is pumped into a volume of
[tex]V_2 = 4.5 L[/tex]
So we can use the equation above to find [tex]p_2[/tex], the final pressure of the gas when it is inside the ball:
[tex]p_2 = \frac{p_1 V_1}{V_2}=\frac{(101.3)(25.0)}{4.5}=562.8 kPa[/tex]
