A 91 kg water skier floating in a lake is pulled from rest to a speed of 13m/s in a distance of 23m. Wha is the bet force exerted on the skier, assuming his acceleration is constant?

Respuesta :

Answer:

F = 1183 N

Explanation:

Given,

The mass of the skier, m = 91 Kg

The initial speed of the skier, u = 0 m/s

The final speed of the skier, v = 13 m/s

The distance traveled by the skier, d = 23 m

The velocity and displacement relation is given by the formula

                                   v = d/t   m/s

∴                                  t = d/v    s

Substituting the given values in the above equation

                                    t = 23 / 13

                                      = 1.769  s

Therefore, the acceleration of the skier,

                                   a = (v-u)/t

                                      = (23 - 0)/ 1.769

                                      = 13 m/s²

The force acting on the skier is given by the formula

                                    F = ma   N

                                       = 91 Kg x 13 m/s²

                                      = 1183 N

Hence, the bet force exerted on the skier, assuming his acceleration is constant is, F = 1183 N