A stationary police car emits a sound of frequency of 1200 HZ that bounces off a car on the highway and returns with a frequency of 1250 HZ. The police car is right next to the highway, so the car is either moving right towards the police car, or away from it. (a) How fast was the car moving? Was it moving towards, or away from the police car? (b) What frequency would the police car have received if it had been moving toward the other car at 20 m/s? Im really trying to understand how to do this problem. Please Show your work.

Question

torichance5204 torichance5204

25-10-2019
Physics

contestada

A stationary police car emits a sound of frequency of 1200 HZ that bounces off a car on the highway and returns with a frequency of 1250 HZ. The police car is right next to the highway, so the car is either moving right towards the police car, or away from it. (a) How fast was the car moving? Was it moving towards, or away from the police car? (b) What frequency would the police car have received if it had been moving toward the other car at 20 m/s? Im really trying to understand how to do this problem. Please Show your work.

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samanthareynee10 samanthareynee10 · Answer 1 · 2019-10-25T09:37:36+02:00

Answer:

First, since the echo frequency is greater, the car must be roaming to the police car.

This is for the reason that the car is "running over" its own wave fronts, creating the wavelengths tinier, and henceforth increasing the frequency.

The trick here is to understand that the relative speed between the cars is half of the speed of the echo for the reason that the echo is returning to the police car at the similar speed as the sound wave trips to the moving car.

It would also appear that the speed of sound has been expected to be 337 m/s

So if v is the moving car's velocity, the correct formula to use is:

2v / 337 = (1250/1200) - 1

2v = 14.04 m/s

v = 7.02 m/s