Answer:
9.05 s
Explanation:
We can solve the problem by using the following suvat equation
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the car in this problem, we know that
u = 22 m/s is the initial velocity
v = 3.0 m/s is the final velocity
[tex]a=-2.1 m/s^2[/tex] is the acceleration (negative since the car is slowing down)
So, by solving the equation for t, we find the time it takes for the car to slow down from 22 m/s to 3.0 m/s:
[tex]t=\frac{v-u}{a}=\frac{3-22}{-2.1}=9.05 s[/tex]
