Answer:
The pack has fallen 275.6 m
Explanation:
The pack is in free fall, so it is moving by uniform accelerated motion, so we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where, choosing upward as positive direction:
v is the final velocity
u is the initial velocity
[tex]a=g=-9.8 m/s^2[/tex] is the acceleration of gravity
s is the vertical displacement
For the pack in this problem,
u = 0
v = -73.5 m/s
Solving for s, we find how far the packet has fallen:
[tex]s=\frac{v^2-u^2}{2a}=\frac{(-73.5)^2-0^2}{2(-9.8)}=-275.6 m[/tex]
And the negative sign means the direction of the displacement is downward.
