Answer:
a)-2m/s^2
b)27.2m/s
Explanation:
Hello! The first step to solve this problem is to find the mass of the block remembering that the definition of weight force is mass by gravity (g=9.8m / s ^ 2)
W=455N=weight
W=mg
W=455N=weight
[tex]m=\frac{W}{g} =\frac{455}{9.81}=46.38kg[/tex]
The second step is to draw the free body diagram of the body (see attached image) and use Newton's second law that states that the sum of the forces is equal to mass by acceleration
[tex]a=\frac{T-W}{m} =\frac{361-455}{46.38kg} =-2m/s^2[/tex]
for point b we use the equations of motion with constant acceleration to find the velocity
[tex]Vf=\sqrt{X(2)(a)+Vo^2}[/tex]
Where
Vf = final speed
Vo = Initial speed
=0
A = acceleration
=2m/s
X = displacement
=6.8m
Solving
[tex]Vf=\sqrt{(6.8)(2)(2)+0^2}=27.2m/s[/tex]
