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Hydrogen peroxide can be prepared by the reaction of barium peroxide with sulfuric acid according to the reaction BaO2(s)+H2SO4(aq)⟶BaSO4(s)+H2O2(aq) How many milliliters of 4.00 M H2SO4(aq) are needed to react completely with 32.7 g BaO2(s)?

Respuesta :

joseaaronlara

Answer:

The answer to your question is: Volume = 15.2 ml

Explanation:

Data

H2SO4 4M  = ?

BaO2          = 32.7 g

                        BaO2(s)  +  H2SO4(aq)  ⟶  BaSO4(s)  +  H2O2(aq)

MW BaO2 = 137 + 32 = 169 g

MW H2SO4 = 2 + 32 + 64 = 98 g

                       169 g of BaO2 -----------------  98 g of H2SO4

                        32.7 g of BaO2 --------------    x

                        x = (32.7 x 98)/ 169

                        x = 18.99 ≈ 19 g of H2SO4

Density of H2SO4 = 1.25 g/lml

Volume = mass / density

Volume = 19 g / 1.25 g/ml

Volume = 15.2 ml

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