the area of a rectangular volleyball court is 1800 square feet the courts length is twice it width write a system of equations that could be used to determine the dimensions in feet of the volleyball court

Respuesta :

Answer:

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

Step-by-step explanation:

Let

x ----> the length of rectangular volleyball court

y ---> the width of the rectangular volleyball court

we know that

The area of the rectangular volleyball court is equal to

[tex]A=xy[/tex]

[tex]A=1,800\ ft^2[/tex]

so

[tex]1,800=xy[/tex] ----> equation A

[tex]x=2y[/tex] -----> equation B

substitute equation B in equation A

[tex]1,800=(2y)y[/tex]

[tex]1,800=2y^2[/tex]

Solve for y

Simplify

[tex]900=y^2[/tex]

take square root both sides

[tex]y=30\ ft[/tex]

Find the value of x

[tex]x=2y[/tex]

substitute the value of y

[tex]x=2(30)=60\ ft[/tex]

therefore

The dimensions of the rectangular volleyball court are 60 ft x 30 ft