Answer:
The momentum of Sam is p = 1350 Kg m/s
Explanation:
Given,
Mass of Sam, m = 75 Kg
The speed at which he leaves the jump, v = 18 m/s
The momentum as he leaves the jump, p = ?
The linear momentum of a body is equal to the mass multiplied by its velocity. It is a vector quantity where it is directed along with the velocity of the body.
The formula for momentum is,
p = mv Kg m/s
Substituting the values in the above equation,
p = 75 Kg x 18 m/s
= 1350 Kg m/s
Hence, the momentum of Sam leaving the jump is p = 1350 Kg m/s