Respuesta :
Answer :
(a) The net ionic equation will be,
[tex]2Cr^{2+}(aq)+3CO_3^{2-}(aq)\rightarrow Cr_2(CO_3)_3(s)[/tex]
The spectator ions are, [tex]NH_4^{+}\text{ and }SO_4^{2-}[/tex]
(b) The net ionic equation will be,
[tex]Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)[/tex]
The spectator ions are, [tex]K^{+}\text{ and }NO_3^{-}[/tex]
(c) The net ionic equation will be,
[tex]Fe^{2+}(aq)+2OH^{-}(aq)\rightarrow Fe(OH)_2(s)[/tex]
The spectator ions are, [tex]K^{+}\text{ and }NO_3^{-}[/tex]
Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
(a) The given balanced ionic equation will be,
[tex]Cr_2(SO_4)_3(aq)+3(NH_4)_2CO_3(aq)\rightarrow 3(NH_4)_2SO_4(aq)+Cr_2(CO_3)_3(s)[/tex]
The ionic equation in separated aqueous solution will be,
[tex]2Cr^{2+}(aq)+3SO_4^{2-}(aq)+6NH_4^{+}(aq)+3CO_3^{2-}(aq)\rightarrow Cr_2(CO_3)_3(s)+6NH_4^{+}(aq)+3SO_4^{2-}(aq)[/tex]
In this equation, [tex]NH_4^{+}\text{ and }SO_4^{2-}[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]2Cr^{2+}(aq)+3CO_3^{2-}(aq)\rightarrow Cr_2(CO_3)_3(s)[/tex]
(b) The given balanced ionic equation will be,
[tex]Ba(NO_3)_2(aq)+K_2SO_4(aq)\rightarrow 2KNO_3(aq)+BaSO_4(s)[/tex]
The ionic equation in separated aqueous solution will be,
[tex]Ba^{2+}(aq)+2NO_3^{-}(aq)+2K^{+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)+2K^{+}(aq)+2NO_3^{-}(aq)[/tex]
In this equation, [tex]K^{+}\text{ and }NO_3^{-}[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)[/tex]
(c) The given balanced ionic equation will be,
[tex]Fe(NO_3)_2(aq)+2KOH(aq)\rightarrow 2KNO_3(aq)+Fe(OH)_2(s)[/tex]
The ionic equation in separated aqueous solution will be,
[tex]Fe^{2+}(aq)+2NO_3^{-}(aq)+2K^{+}(aq)+2OH^{-}(aq)\rightarrow Fe(OH)_2(s)+2K^{+}(aq)+2NO_3^{-}(aq)[/tex]
In this equation, [tex]K^{+}\text{ and }NO_3^{-}[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
[tex]Fe^{2+}(aq)+2OH^{-}(aq)\rightarrow Fe(OH)_2(s)[/tex]
