Answer:
[tex]1.5 \Omega[/tex]
Explanation:
The resistance of a piece of wire is given by
[tex]R=\frac{\rho L}{A}[/tex]
where
[tex]\rho[/tex] is the resistivity of the material
L is the length of the wire
A is the cross-sectional area
In this problem, we have
[tex]\rho = 3.3\cdot 10^{7} m[/tex]
L = 7.0 m
The diameter of the wire is 0.14 cm, so the radius is 0.07 cm, therefore the cross sectional area is
[tex]A=\pi r^2 = \pi (0.07)^2=0.0154 cm^2 = 0.0154\cdot 10^{-4} m^2[/tex]
Therefore, the resistance is
[tex]R=\frac{(3.3\cdot 10^{-7})(7.0)}{(0.0154\cdot 10^{-4})}=1.5 \Omega[/tex]
