Answer:
Specific rotation of cholesterol is -3.15°.
Explanation:
Given that
Path length = 10 cm = 1 dm.
Observed rotation ,α= - 0.441 °
m= 0.14 g
V= 1 ml
The concentration of cholesterol ,c= m/V g/ml
c = 0.14 / 1 = 0.14 g/ml
We know that specific rotation given as
[tex][\alpha]_D=\dfrac{\alpha}{l.c}[/tex]
Now by putting the all values
[tex][\alpha]_D=\dfrac{\alpha}{l.c}[/tex]
[tex][\alpha]_D=\dfrac{-0.441}{1\times 0.14}[/tex]
[tex][\alpha]_D=-3.15[/tex]°
Specific rotation of cholesterol is -3.15°.
