The weekly demand for a company's frozen pizzas varies directly as the amount spent on advertising and inversely as the price per pizza. At $5 per piza, when $500 is spent each week on ads, the demand is 2000 pizzas. When advertising is increased to $600, what price per pizza yields a demand of 2000 pizzas?

Respuesta :

The price per pizza yields a demand of 2000 pizza is $6, when advertising is increased to $600

Step-by-step explanation:

Direct and inverse proportion:

  • If y varies directly with x (y ∝ x), then y = k x, where k is the constant of variation
  • If y varies inversely with x (y ∝ [tex]\frac{1}{x}[/tex] ), then [tex]y=\frac{k}{x}[/tex] , where k is the constant of variation
  • If y varies directly with x and inversely with z (y ∝ [tex]\frac{x}{z}[/tex] ), then [tex]y=k*\frac{x}{z}[/tex] , where k is the constant of variation

The weekly demand for a company's frozen pizzas varies directly as the amount spent on advertising and inversely as the price per pizza

Assume that the weekly demand for a company's frozen pizzas is y, the amount spent on advertising is $x and the price per pizza is $z

∵ The weekly demand "y" varies directly as the amount spent on

   advertising "$x"

∴ y ∝ x

∵ The weekly demand "y" varies inversely as the price per pizza "$z"

∴ y ∝ [tex]\frac{1}{z}[/tex]

∴ y ∝ [tex]\frac{x}{z}[/tex]

∴ [tex]y=k*\frac{x}{z}[/tex]

To find the value of k substitute x , y and z by their initial amount

∵ The price per pizza is $5

∴ z = 5

∵ $500 is spent each week on ads

∴ x = 500

∵ The demand is 2000 pizzas

∴ y = 2000

- Substitute these values in the equation of y above

∵ [tex]2000=k*\frac{500}{5}[/tex]

∴ 2000 = k(100)

- Divide both sides by 100

20 = k

- Substitute the value of k in the equation

∴ [tex]y=20*\frac{x}{z}[/tex]

∵ Advertising is increased to $600

∴ x = 600

∵ The demand is 2000 pizzas

∴ y = 2000

- To find the price per pizza "z" under this condition substitute the

  values of x and y in the equation below

∵ [tex]y=20*\frac{x}{z}[/tex]

∴ 2000 = 20 × [tex]\frac{600}{z}[/tex]

- Divide both sides by 20

∴ 100 = [tex]\frac{600}{z}[/tex]

- Multiply both sides by z

∴ 100 z = 600

- Divide both sides by 100

z = 6

∴ The price per pizza = $6

The price per pizza yields a demand of 2000 pizza is $6, when advertising is increased to $600

Learn more:

You can learn more about direct and inverse proportion in brainly.com/question/10708697

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