Answer:
482853.39714 A/m²
[tex]3.55\times 10^{-5}\ m/s[/tex]
Explanation:
I = Current = 2.54 A
d = Diameter = 2.588 mm
r = Radius = [tex]\frac{d}{2}=\frac{2.588}{2}=1.294\ mm[/tex]
A = Area = [tex]\pi r^2[/tex]
n = Charge density = [tex]8.48\times 10^{28}\ electrons/m^3[/tex]
q = Charge of electron = [tex]1.6\times 10^{-19}\ C[/tex]
Current density
[tex]J=\frac{I}{A}\\\Rightarrow J=\frac{2.54}{\pi (1.294\times 10^{-3})^2}\\\Rightarrow J=482853.39714\ A/m^2[/tex]
The current density is [tex]482853.39714\ A/m^2[/tex]
Drift velocity
[tex]v_d=\frac{I}{nqA}[/tex]
[tex]I=JA[/tex]
[tex]\\\Rightarrow v_d=\frac{J}{nq}\\\Rightarrow v_d=\frac{482853.39714}{8.48\times 10^{28}\times 1.6\times 10^{-19}}\\\Rightarrow v_d=3.55\times 10^{-5}\ m/s[/tex]
The drift velocity magnitude is [tex]3.55\times 10^{-5}\ m/s[/tex]
