Respuesta :
Answer:
1. Oxidant - Cl₂, n = 6
2. Oxidant - Hg²⁺, n = 2
3. Oxidant - MnO₄⁻, n = 6
Explanation:
Oxidant or Oxidizing agent, is a species that gets reduced by gaining electrons and oxidizes the other species.
1. 2Fe + 3Cl₂ → 2FeCl₃
In this reaction, Fe atom loses 3 electrons each and gets oxidized from 0 oxidation state in Fe to +3 oxidation state in FeCl₃. Whereas, Cl atom gains 1 electron each and gets reduced from 0 oxidation state in Cl₂ to -1 oxidation state in FeCl₃. Therefore, Cl₂ is the oxidizing agent.
Now the total number of electrons lost by 2 Fe atoms = total number of electrons gained by 6 Cl atoms = 6.
Therefore, number of electrons transferred (n) = 6.
2. H₂O + Hg²⁺ + NO₂⁻ → 2H⁺ + Hg + NO₃⁻
In this reaction, N loses 2 electrons and gets oxidized from +3 oxidation state in NO₂⁻ to +5 oxidation state in NO₃⁻. Whereas, Hg gains 2 electrons and gets reduced from +2 oxidation state in Hg²⁺ to 0 oxidation state in Hg. Therefore, Hg²⁺ is the oxidizing agent.
Now the total number of electrons lost by N = total number of electrons gained by Hg = 2
Therefore, number of electrons transferred (n) = 2
3. 3SO₃²⁻ + 2MnO₄⁻ + H₂O → 3SO₄²⁻ + 2MnO₂ + 2OH⁻
In this reaction, each S atom loses 2 electrons and gets oxidized from +4 oxidation state in SO₃²⁻ to +6 oxidation state in SO₄²⁻. Whereas, each Mn atom gains 3 electrons and gets reduced from +7 oxidation state in MnO₄⁻ to +4 oxidation state in MnO₂. Therefore, MnO₄⁻ is the oxidizing agent.
Now the total number of electrons lost by 3 S atoms = total number of electrons gained by 2 Mn atoms = 6
Therefore, number of electrons transferred (n) = 6
