Answer:
The diver will be in free fall for [tex]10\sqrt{3}[/tex] seconds.
Step-by-step explanation:
The distance in feet, that an object falls in t seconds is given by the function [tex]h(t) = 16t^{2}[/tex].
Now, given that the height is 4800 feet and we have to calculate the number of seconds the diver was in a free fall.
Therefore, [tex] 4800 = 16t^{2}[/tex]
⇒ [tex]t^{2} = \frac{4800}{16} = 300[/tex]
⇒ [tex]t = \sqrt{300} = \sqrt{100 \times 3} = 10\sqrt{3}[/tex] seconds.
Therefore, the diver will be in free fall for [tex]10\sqrt{3}[/tex] seconds. (Answer)
