Answer:
[tex]\pm{\frac{3}{4}}[/tex] to the 2nd power equals [tex]\frac{9}{16}[/tex]
Step-by-step explanation:
Let the unknown number which is raised to 2nd power be = [tex]x[/tex]
So, the expression can be written as:
[tex]x^2=\frac{9}{16}[/tex]
Solving for [tex]x[/tex]
Taking square root both sides to remove the 2nd power.
[tex]\sqrt{x^2}=\pm\sqrt{\frac{9}{16}}[/tex]
[tex]x=\pm\sqrt{\frac{9}{16}}[/tex]
Since 9 and 16 are perfect square, we can write them in 2nd powers of 3 and 4 respectively.
[tex]x=\pm\sqrt{\frac{3^2}{4^2}}[/tex]
∴ [tex]x=\pm{\frac{3}{4}}[/tex]
