Answer:
True.
Step-by-step explanation:
Given,
4cos2 (4x) - 3 = 0
Now, 4π/24 = π/6
Or, cos π/6 = √3/2
Or, cos^2 π/6 = 3/4
Or, 4 cos^2 π/6 = 3
Now, Left Hand Side= 4cos2 (4x) - 3
= 3-3 =0 = Right Hand Side (Proved)
Here, Left Hand Side= Right Hanad Side. So, 4cos2 (4x) - 3=0 is true.
Answer:
True statement
Explanation:
Given the equation, [tex]4cos^2 (4x)-3[/tex]= 0
On solving,
[tex]4 \cos ^{2}(4 x)=3[/tex]
[tex]\cos ^{2}(4 x)=\frac{3}{4}[/tex]
Taking square root both sides
We get,
[tex]\cos 4 x=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\sqrt{3}}{2}=\cos \frac{\pi}{6}[/tex]
Putting it in the equation
[tex]\cos 4 x=\cos \frac{\pi}{6}[/tex]
[tex]4 x=\frac{\pi}{6}[/tex]
x = π/24
