The work done on the car is [tex]2.35\cdot 10^5 J[/tex]
Explanation:
The work done by a force exerted on an object is given by
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement of the object
[tex]\theta[/tex] is the angle between the direction of the force and the displacement
In this problem, we have
F = 1080 N is the cumulative force applied on the car
d = 218 m is the displacement of the car
[tex]\theta=0^{\circ}[/tex] (assuming the force is applied in the same direction of motion of the car)
Substituting into the equation, we find the work done:
[tex]W=(1080)(218)(cos 0)=2.35\cdot 10^5 J[/tex]
Learn more about work:
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