Respuesta :
Answer: The amount of nitrogen gas produced is 3.864 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of [tex]NaN_3[/tex] = 6.00 g
Molar mass of [tex]NaN_3[/tex] = 65 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of }NaN_3=\frac{6.00g}{65g/mol}=0.092mol[/tex]
For the given chemical reaction:
[tex]2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)[/tex]
By Stoichiometry of the reaction:
2 moles of [tex]NaN_3[/tex] produces 3 moles of nitrogen gas
So, 0.092 moles of [tex]NaN_3[/tex] will produce = [tex]\frac{3}{2}\times 0.092=0.138mol[/tex] of nitrogen gas
Now, calculating the mass of nitrogen gas by using equation 1, we get:
Molar mass of nitrogen gas = 28 g/mol
Moles of nitrogen gas = 0.138 moles
Putting values in equation 1, we get:
[tex]0.138mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.138mol\times 28g/mol)=3.864g[/tex]
Hence, the amount of nitrogen gas produced is 3.864 grams
