Answer:
[tex]I=20W/m^2[/tex]
Explanation:
Since intensity is proportional to [tex]1/r^2[/tex], being at a distance 5 times farther will make the intensity 25 times smaller, which means that the intensity for an outer planet located at a distance 5 R from the Sun is:
[tex]I=\frac{I_0}{25}=\frac{500W/m^2}{25}=20W/m^2[/tex]