Answer:
1. The equivalence volume would be the same.
4. The initial pH would be the same.
Explanation:
The reactions of KHP with HCl and NaOH are:
KHP + HCl → H₂P + KCl
KHP + NaOH → P²⁻ + H₂O + K⁺ + Na⁺
As the molar concentration of HCl and NaOH are the same, 1. The equivalence volume would be the same.
The pH will not be the same because with HCl you are adding acid decreasing pH and for the second reaction NaOH is a base that increase pH. For the same reason, in the midpoint pH wouldn't be the same.
Phenolphtalein wouldn't be an appropriate indicator because the useful pH range is between 6,0 and 7,6 and the equivalence points are in 7,2 and 10,6.
4. The initial pH would be the same. That's true because in the two titrations you will have just 0,20M KHP in solution.
I hope it helps!
Given the Chemical Reaction we decipher that, The equivalence volume would be the same. and The initial pH would be the same.
Option A and D is correct
Question Parameter(s):
a titration of 0.20 M KHP with 0.20 M HCl as the titrant
your titration with 0.20 M NaOH as the titrant in the la
Generally, the equation for the Chemical Reaction is mathematically given as
KHP + HCl ----> H₂P + KCl
KHP + NaOH ----> P^{2-} + H2O + K+ + Na+
In conclusion, Since molar concentration of HCl is same with the molar concentration of NaOH,The equivalence volume would be the same, and The initial pH would be the same
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