Answer:
The perimeter of the given triangle is 19.24 cm.
Step-by-step explanation:
Here, the given triangle is a right angled triangle.
Perpendicular AB = 5 cm
Hypotenuse AC = 8 cm
Let us assume the base AB = k units
Now, by PYTHAGORAS THEOREM in a right angled triangle:
[tex](Base)^2 + (Perpendicular)^2 = (Hypotenuse)^2[/tex]
Here, in ΔABC
[tex](AB)^2 + (BC)^2 = (AC)^2\\\implies (x)^2 + (5) ^2 = (8) ^2\\\\x^2 = 64 - 25 = 39\\\implies x = \sqrt{39} = 6.24[/tex]
⇒ AB = 6.24 cm
Now, the PERIMETER OF A TRIANGLE = AB + BC + AC
= 6.24 cm + 8 cm + 5 cm = 19.24 cm
Hence, the perimeter of the given triangle is 19.24 cm.
