Suppose you observed 32 whitefish blastula cells. One cell was in metaphase, 3 were in anaphase, 8 were in prophase, and 4 were in telophase. Assuming you assigned a cell cycle phase to each of the 32 cells, calculate the percent of time the whitefish blastula cells spend in interphase.

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Answer:

Explained

Explanation:

Eight prophase cells, one metaphase cell,three anaphase cells, and four telophase cells. It results in 8 + 1+ 3 + 4 = 16 cells.This indicates that the remaining cells of 32-16 = 16 were in interphase.This means the cells spend the maximum amount of time in interphase.This time is equal to half the total cells.

So, if it's a 24-hour process,the interphase should spend 12 hours.

Six hours of prophase, 45 minutes in metaphase and 2 hour, 15 minutes in anaphase, and 3 hours in telophase.

Answer:

50%

Explanation:

1 cell in metaphase + 3 cells in telophase + 8 cells in prophase + 4 in telophase = 16 cells in mitosis

32 cells total − 16 cells in mitosis = 16 cells in interphase

(16 cells in interphase / 32 cells total) × 100 = 50%