Answer:
angular resolution = 0.07270° = 1.269 × [tex]10^{-3}[/tex] rad
greatest distance from the camera = 118.20 m = 0.118 km
Explanation:
given data
diameter = 0.50 mm = 0.5 × [tex]10^{-3}[/tex] m
distance apart = 15 cm = 15× [tex]10^{-2}[/tex] m
wavelength λ = 520 nm = 520 × [tex]10^{-9}[/tex] m
to find out
angular resolution and greatest distance from the camera
solution
first we expression here angular resolution that is
sin θ = [tex]\frac{1.22* \lambda }{D}[/tex] .......................1
put here value λ is wavelength and d is diameter
we get
sin θ = [tex]\frac{1.22*520*10^{-9}}{0.5*10^{-3}}[/tex]
θ = 0.07270° = 1.269 × [tex]10^{-3}[/tex] rad
and
distance from camera is calculate here as
θ = [tex]\frac{I}{r}[/tex] .................2
I = [tex]\frac{15*10^{-2}}{1.269*10^{-3}}[/tex]
I = 118.20 m = 0.118 km
