I need help. Can you please explain to me how to do this?

The solution of given system of equations is
x=8, y=3
Step-by-step explanation:
Given equations are:
[tex]-2x+9y=11\ \ \ \ \ Eqn\ 1-5x+2y=-34\ \ \ \ \ Eqn\ 2[/tex]
Multiplying eqn 1 by 5
[tex]-10x+45y=55\ \ \ \ Eqn\ 3[/tex]
Multiplying eqn 2 by 2
[tex]-10x+4y=-68\ \ \ \ Eqn 4[/tex]
Subtracting eqn 4 from eqn 3
[tex]-10x+45y-(-10x+4y)=55-(-68)\\-10x+45y+10x-4y=55+68\\41y=123[/tex]
Dividing both sides by 41
[tex]\frac{41y}{41}=\frac{123}{41}\\y=3[/tex]
Putting y=3 in equation 1
[tex]-2x+9(3)=11\\-2x+27=11\\-2x=11-27\\-2x=-16[/tex]
Dividing both sides by -2
[tex]\frac{-2x}{-2}=\frac{-16}{-2}\\x=8[/tex]
Hence,
The solution of given system of equations is
x=8, y=3
Keywords: Linear equations, Variables
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