Bianca is standing at x =600m. Firecracker 1, at the origin, and firecracker 2, at x =900m, explode simultaneously. The flash from firecracker 1 reaches Bianca's eye at 4.0 μs . Part A At what time does she see the flash from firecracker 2?

Respuesta :

Answer:[tex]3 \mu s[/tex]

Explanation:

Given

Bianca is at [tex]x=600 m[/tex]

i.e. distance between origin and Bianca is [tex]600 m[/tex]

time taken to reach Bianca eyes is

[tex]t=\frac{600}{speed\ of\ light}[/tex]

[tex]t=\frac{600}{3\times 10^8}[/tex]

[tex]t=2\times 10^{-6} s[/tex]

[tex]t=2 \mu s[/tex]

i.e. Cracker exploded at [tex]t=2\mu s[/tex] because it is observed at [tex]t=4\mu s[/tex]

Time taken by second cracker flash to reach Bianca eyes

[tex]t_2=\frac{300}{3\times 10^8}[/tex]

[tex]t_2=10^{-6}[/tex]

[tex]t_2=1 \mu s[/tex]

Therefore it will be observed at [tex]t=3 \mu s[/tex]