Respuesta :

Manetho

Answer:

[tex]r_m= rsin\theta[/tex]

Explanation:

from the figure in the attachment we can write

Torque about point p

[tex]\tau=-Frsin(180-\theta)[/tex] ( negative sign because of sign convention, out ward positive in ward ingative)

For the length r_m we can write

[tex]Sin\theta= \frac{r_m}{r}[/tex]

therefore,

[tex]r_m= rsin\theta[/tex]

Ver imagen Manetho
ardni313

rm = r sin θ

τ = -r sin θ F

Further explanation

Torque (moment of force) with respect to the pivot point P is defined as the product of the magnitude of the force F and the moment's arm

τ = l . F

The torque can be clockwise or counterclockwise (counterclockwise marked +, clockwise marked -)

For objects with 2 or more forces, the total torque is:

Στ = τ1 + τ2 + ... τn

From pictures attached

τ = -rm  x F

rm = (arm force which is perpendicular to the work line)

⇒ negative sign because the torque is clockwise  to the point P

while the magnitude of the arm force rm:

rm = r sin θ

Learn more

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static equilibrium

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Newton's Law

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