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Using Hooke's Law, you find the spring constant of a given spring to be 8.0 N/m 0.6 N/m. Your lab partner uses simple harmonic motion and finds the spring constant to be 8.9 N/m 0.5 N/m. Would you consider these two springs to have the same spring constant?

a. yes

b. no

c. not enough info

Respuesta :

Answer:Yes

Explanation:

Given

Using Hooke's law value of spring constant is

[tex]k_1=8 N/m[/tex]

[tex]k_2=0.6 N/m[/tex]

so the range of k varies from [tex]k_1-k_2\ to\ k_1+k_2[/tex]

i.e. from 8-0.6 to 8+0.6=7.4 to 8.6 N/m

From SHM experiment

Spring constant obtained are

[tex]k_a=8.9 N/m[/tex]

[tex]k_b=0.5 N/m[/tex]

range [tex]=k_a-k_b\ to\ k_a+k_b[/tex]

range=8.9-0.5  to 8.9+0.5

range=8.4 to 9.4 N/m

as both range is coinciding at some Point therefore it can be consider that the spring is same                

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