Answer:
Center of mass lies 24 m in front of center of mass of second wagon.
Explanation:
Suppose A 1200 kg station wagon is moving along a straight highway at 12.0 m/s. Another car with mass 1800 kg and speed 20.0 m/s.
Given that,
Mass of first wagon = 1200 kg
Mass of second wagon = 180 kg
Distance = 40 m
We need to calculate the position of the center of mass of the system
Using formula of center mass
[tex]x_{cm}=\dfrac{m_{1}x_{1}+m_{2}x_{2}}{m_{1}+m_{2}}[/tex]
[tex]x_{cm}=\dfrac{1200\times0+1800\times40}{1200+1800}[/tex]
[tex]x_{cm}=24\ m[/tex]
Hence, Center of mass lies 24 m in front of center of mass of second wagon.
