What is the area of this triangle? Enter your answer as a decimal in the box. Round only your final answer to the nearest hundredth. ft² The figure contains a triangle. One side is 2.7 feet. A second side is 3.4 feet. The angle between the given sides is 40 degrees.

Respuesta :

Answer:

Area of the triangle [tex]\simeq[/tex] 5.9 sq. ft. .

Step-by-step explanation:

Length of two sides of the triangle are, 2.7 feet and 3.4 feet and the angle between them is 40° .

So, the area of the triangle is given by,

[tex]2.7 \times 3.4 \times \sin {40^{\circ}}[/tex]  sq. ft.

[tex]\simeq 5.9[/tex] sq. ft.

Answer:

The area of triangle is [tex]3.42 \mathrm{ft}^{2}[/tex]

Explanation:

We are given two sides of a triangle and their including angle.

The two given sides of a triangle are , one is 2.7 ft and other is 3.4 ft

And the including angle is given to be 40°

The formula to find area of triangle when two sides and their including angle is given is-

=[tex]\frac{a b \sin \theta}{2}[/tex]

where a and b are two sides and θ is the including angle.

Substituting the given values,  

Area =[tex]\frac{2.7 \times 3.4 \times \sin 40^{\circ}}{2}[/tex]

 = [tex]\frac{2.7 \times 3.4 \times 0.74}{2}[/tex]

= 3.42

Hence [tex]3.42 \mathrm{ft}^{2}[/tex] is the area of triangle.