Answer:
0.000324 kg/m²h
Explanation:
[tex]c_h[/tex] = High concentration = 2 kg/m³
[tex]c_l[/tex] = Low concentration = 0.2 kg/m³
[tex]x_h[/tex] = One Length = 0
[tex]x_l[/tex] = Other Length = 2 mm
D = Diffusion coefficient = [tex]1\times 10^{-10}\ m^2/s[/tex]
The flow rate through a wall from Fick's Law is given by
[tex]J_x=-D\frac{\partial c}{\partial x}\\\Rightarrow J_x=-D\frac{c_h-c_l}{x_h-x_l}\\\Rightarrow J_x=-1\times 10^{-10}\times 3600\times \frac{2-0.2}{0-2\times 10^{-3}}\\\Rightarrow J_x=0.000324\ kg/m^2h[/tex]
The flow rate through the wall is 0.000324 kg/m²h