Respuesta :
Answer:
1) Enthalpy of reaction per gram of quick lime or calcium oxide is -6.25 kJ/g.
2)[tex]4.730\times 10^6 [/tex]kilo Joules of energy is produced when 1 Tonn of slaked lime is produced.
Explanation:
[tex]CaO(s) + H_2O(l)\rightarrow Ca(OH)_2(s),\Delta H=-350 kJ/mol[/tex]
Enthalpy of reaction = ΔH = -350 kJ/mol
1 mole of calcium oxide = 56 g/mol
1 ) Enthalpy of reaction per gram of quick lime or calcium oxide:
[tex]\frac{\Delta H}{56 g/mol}=\frac{-350 kJ/mol}{56 g/mol}=-6.25 kJ/g[/tex]
2) Mass of slake lime = 1 Tonn = 1,000,000 g
Moles of slaked lime = [tex]\frac{1,000,000}{74 g/mol}=13,513.51 mol[/tex]
According to reaction, on formation of 1 mol of slaked lime 350 kilo Joules of energy is produced.
Then energy produced when 13,513.51 moles of slaked lime is produced:
[tex]350 kJ\times 13,513.51 =4.730\times 10^6 kJ[/tex]
[tex]4.730\times 10^6 [/tex]kilo Joules of energy is produced when 1 Tonn of slaked lime is produced.
