Answer:
Friction = 15.80 Newton
Explanation:
given
A pulling force (F) is 70N acting on the block of 10kg (M) which is placed on the ramp which is at an angle of 20° with the horizontal.
Irrespective to the ramp ,Weight of the body acts vertically downward , if we resolve the components of W=Mg as Mgsin20° (along the ramp) and Mgcos20° (perpendicular to the ramp) as shown in the attachment which contains FBD of the block
as given the body is Accelerating with an acceleration (a) of 2 m/[tex]s^{2}[/tex] due to the pulling force . As friction always opposes the motion it acts in the backward direction to the pulling force .as shown in the figure attached
By Newton's 2nd Law
Ma = F - MgSin20°-friction
by subtituting the values we get
10(2) = 70 - 10(10)sin20° - friction
friction =70 - 100sin20° -20
friciton = 15.7979N
by rounding of ,
Frictional force is 15.80 Newton
