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A particle with charge q and kinetic energy K travels in a uniform magnetic field of magnitude B. If the particle moves in a circular path of radius R, find expressions for each of the following. (Use any variable or symbol stated above as necessary.)

Respuesta :

Manetho

Answer:

Explanation:

In this question it is assumed that expressions for speed and mass are asked

Kinetic energy

[tex]KE= 0.5mv^2[/tex]

since the charge moving in a circle

[tex]qvB= mv^2/r[/tex]

So we can write

[tex]v= \frac{2KE}{qBr}[/tex]

so, the expression for speed

[tex]v= \frac{2KE}{qBr}[/tex]

now to obtain the expression for mass

Force F = m×a

and so solving for m we get:

plug expression for v back into KE equation

[tex]KE= \frac{1}{2}m(\frac{2KE}{qBr})^2[/tex]

now rearranging the above equation we get

[tex]m= \frac{(qBr)^2}{2KE}[/tex]

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