Answer:
When [tex]x= 3[/tex], both expressions have a value of 30.
When [tex]x= 1[/tex]. both expressions have a value of 18, and when [tex]x= 8[/tex], both expressions have a value of 60.
Step-by-step explanation:
Given:
[tex]4(x+3)+2x = 6(x+2)[/tex]
Solving the equation further we get:
[tex]4(x+3)+2x= 6(x+2)\\ 4x+12+2x=6x+12\\6x+12=6x+12 \ \ \ \ equation \ 1[/tex]
Now, When [tex]x=3[/tex], both expressions have a value of 30.
Substituting Value of x in equation 1 we get,
[tex]6x+12=6x+12\\6\times 3+12 = 6\times 3+12\\18+12=18+12\\30=30[/tex]
Hence the above Statement proves as Correct with given values.
Now, When [tex]x=-5[/tex], both expressions have a value of 42.
Substituting Value of x in equation 1 we get,
[tex]6x+12=6x+12\\6\times -5+12 = 6\times -5+12\\-30+12=-30+12\\-18=-18[/tex]
Hence the above Statement does not proves as Correct with given values.
Now,When[tex]x=1[/tex], both expressions have a value of 18, and when [tex]x=8[/tex], both expressions have a value of 60.
Substituting Value of x in equation 1 we get,
[tex]6x+12=6x+12\\6\times 1+12 = 6\times 1+12\\6+12=6+12\\18=18[/tex]
[tex]6x+12=6x+12\\6\times 8+12 = 6\times 8+12\\48+12=48+12\\60=60[/tex]
Hence the above Statement proves as Correct with given values.
When [tex]x=-2[/tex]. both expressions have a value of 15, and when [tex]x=-6[/tex], both expressions have a value of 39.
Substituting Value of x in equation 1 we get,
[tex]6x+12=6x+12\\6\times -2+12 = 6\times -2+12\\-12+12=-12+12\\0=0[/tex]
[tex]6x+12=6x+12\\6\times -6+12 = 6\times -6+12\\-36+12=-36+12\\-24=-24[/tex]
Hence the above Statement does not proves as Correct with given values.
