Answer: [tex]37.5^{\circ}[/tex] or [tex]37\dfrac{1}{2}^{\circ}[/tex]
Step-by-step explanation:
Given : The temperature of the liquid changed by [tex]-82\dfrac{1}{2}^{\circ}C[/tex] over [tex]2\dfrac{1}{5}[/tex] minutes.
We can write [tex][tex]82\dfrac{1}{2}=\dfrac{82\times2+1}{2}=\dfrac{165}{2}[/tex]
[tex]2\dfrac{1}{5}=\dfrac{11}{5}[/tex]
Now, the statement becomes ,
The temperature of the liquid changed by [tex]-\dfrac{165}{2}^{\circ}C[/tex] over [tex]\dfrac{11}{5}[/tex] minutes.
i.e. temperature changed in [tex]\dfrac{11}{5}[/tex] minutes = [tex]-\dfrac{165}{2}^{\circ}C[/tex]
Now, by Unitary method,
The temperature changed in 1 minute = [tex]\dfrac{165}{2}\times\dfrac{5}{11}^{\circ}C[/tex]
⇒ The temperature changed in 1 minute = [tex]37.5^{\circ}[/tex] or [tex]37\dfrac{1}{2}^{\circ}[/tex]
