Answer:
It would take 3.00 s
Step-by-step explanation:
For a constant force system, the acceleration (a) of the system is constant.
In the first instance,
Initial velocity = 0 mph
final velocity = 29.0 mph
time taken = 1.50 s
[tex]acceleration = \frac{final velociity(v) - initial velocity (u)}{time taken}[/tex]
[tex]acceleration = \frac{29.0 - 0}{1.50}[/tex]
[tex]acceleration = 19.33 mph^{2}[/tex]
Since the system is a constant force system,
Initial velocity = 0 mph
final velocity = 58.0 mph
time taken = ?
[tex]acceleration = \frac{final velociity(v) - initial velocity (u)}{time taken}[/tex]
[tex]19.33 = \frac{58.0 - 0}{t}[/tex]
t = \frac{58.0}{19.33} = 3.00 s
