1) The wavelength of the wave is 5 metres
2) The frequency of the wave is 0.05 Hz
3) The wave velocity is 0.25 m/s
Explanation:
1)
The wavelength of a wave (represented with [tex]\lambda[/tex]) is the smallest distance between two points of the wave having the same shape. For instance, it can be measured as the distance between two consecutive crests of a wave (or the distance between two consecutive troughs).
For the wave in this problem, we have that the distance between the crests is 5 metres.
Therefore, the wavelength corresponds to this distance:
[tex]\lambda = 5 m[/tex]
2)
The frequency of a wave (represented with [tex]f[/tex]) is the number of complete cycles of the wave per unit time.
The frequency can be calculated as the number of crests of the wave (N) passing a given point per second:
[tex]f=\frac{N}{t}[/tex]
where t is the time.
The frequency can also be calculated as the reciprocal of the period (T), which is the time the wave takes for one complete oscillation:
[tex]f=\frac{1}{T}[/tex]
For the wave in this problem, one crest passes you every 20 seconds: this means that the period of the wave is 20 seconds,
T = 20 s
So the frequency is
[tex]f=\frac{1}{20}=0.05 Hz[/tex]
3)
The velocity of a wave is given by the wave equation:
[tex]v=f \lambda[/tex]
where
f is the frequency of the wave
[tex]\lambda[/tex] is its wavelength
For the wave in the problem,
f = 0.05 Hz
[tex]\lambda = 5 m[/tex]
Substituting,
[tex]v=(0.05)(5)=0.25 m/s[/tex]
Learn more about waves:
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