Answer:
Explanation:
From the question, we know that;
2H+H^+ ----->H^3+, ∆H°=-849 kilojoule per mole --------------(1).
H2 --------------->2H, DH° = 436.6 kilojoule per mole ---------------(2).
Adding the equation (1) and equation (2) above gives another equation of reaction, which is;
H2 + H^+ --------------> H^3+ --------------------------------------------(3)
∆H° = [-(849) - (+436.4)] kilojoule per mole.
∆H°=[-(849) - 436.4] kilojoule per mole....
∆H= - 1,285.4 kilojoule per mole