Answer:
t = 1964636.542 sec
Explanation:
Given data:
sphere diameter is 10 mm
Density is 1150 kg/m^3
viscosity 105 N s/m^2
We knwo that time taken by sphere can be calculated by following procedure
[tex]\tau = \mu \frac{du}{dy}[/tex]
[tex]\frac{F}{A} = \mu \frac{du}{r} [/tex]
[tex]\frac{\rho_C -\rho_{asphalt} gv}{2 \pi rL} = 10^5 \frac{du}{r}[/tex]
Solving for du
[tex]du = \frac{ (8933 - 1150) 9.81 \frac{4}{3} \pi (10\times 10^{-3})^3}{2\pi \times 1\times 10^5}[/tex]
[tex]du = u = 5.09\times 10^{-7}[/tex]
[tex]u = \frac{1}{t}[/tex]
[tex]t = \frac{1}{5.09\times 10^{-7}} = 1964636.542 sec[/tex]
