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A 55-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.30. A horizontal 140-n force is applied to the box. What is the friction force on the box?

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Answer:

The friction force on the box is 161.7 N

Explanation:

given information:

m = 55 kg

μs = 0.30

F = 140 N

To calculate the friction force, we use the following formula:

F(friction) = μs N,

N is normal force

N -  W = 0

N = W

   = m g

Thus,

F(friction) = μs N

                = μs  m g

                = 0.3 x 55 x 9.8

                = 161.7 N

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