Answer:
22.3Ns
Explanation:
Hi!
To solve this exercise follow the steps below.
1. Find the weight of the stone by multiplying the gravity (9.8m / s ^ 2) by the mass.
W=mg
m=mass=2.5kg
g=gravity=9.8m / s ^ 2
W=(2.5)(9.8)=25.5N
2. Find the time it takes for the stone to touch the ground using the kinematic equation for constant acceleration.
Vf=Vo+a.t
y= VoT+\frac{1}{2}gt^{2}
Where
Vo = Initial speed =0
T = time
g=gravity=9.8m/s^2
Y= height= 3.75m
solving for time
[tex]2y=gt^2\\t=\sqrt{ \frac{2y}{g} }=\sqrt{ \frac{2(3.75)}{9.8} }=0.87s[/tex]
3. For a constant force such as weight, the impulse is calculated as the product between force and time.
I=wt
I=(25.5N)(0.87S)=22.3Ns
