Answer:
1.69 moles of ammonia are needed to produced 45.5 g of water.
Explanation:
Given data:
Mass of water = 45.5 g
Moles of ammonia required = ?
Solution:
Chemical equation:
4NH₃ + 5O₂ → 4NO + 6H₂O
Number of moles of water:
Number of moles = mass/ molar mass
Number of moles = 45.5 g/ 18 g/mol
Number of moles = 2.53 mol
Now we will compare the moles of water with ammonia.
H₂O : NH₃
6 : 4
2.53 : 4/6×2.53 = 1.69 mol
1.69 moles of ammonia are needed to produced 45.5 g of water.
