Answer:
[tex]\sqrt{2}[/tex] units
Step-by-step explanation:
The Line 1 has equation x + y = 5 ....... (1) , and
Line 2 has equation x + y = 3 .......... (2)
Now, we have to find the perpendicular distance between line 1 and line 2.
We can say that (3,0) is a point on line 2 as it satisfies the equation (2).
Now, the perpendicular distance from point (3,0) to the line 1 will be given by the formula
[tex]\frac{|3 + 0 - 5|}{\sqrt{1^{2}+ 1^{2}}} = \frac{2}{\sqrt{2}} = \sqrt{2}[/tex] units (Answer)
We know that the perpendicular distance from any external point ([tex]x_{1},y_{1}[/tex]) to a given straight line ax + by + c = 0 is given by the formula [tex]\frac{|ax_{1} + by_{1} + c|}{\sqrt{a^{2} + b^{2}}}[/tex].
