Answer:
2680 mL
Explanation:
Given data:
Mass of calcium sulfide = 48 g
Molarity of solution = 0.250 M
Volume required = ?
Solution;
Number of moles = mass/molar mass
Number of moles = 48 g/72.143 g/mol
Number of moles = 0.67 mol
Volume:
Molarity = number of moles / volume in litter
Volume in litter = number of moles / Molarity
Volume in litter = 0.67 mol /0.250 M
Volume in litter = 2.68 L
Litter to mL:
2.68L × 1000 mL/1 L= 2680 mL
