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What is the concentration of a solution prepared by placing 20. mL of 0.12 M K2S in a graduated cylinder and pouring water until you reach the 100.0 mL mark (the final volume after mixing the solution with water is 100.0 mL).

Respuesta :

Answer: 0.024 M

Explanation:

According to the neutralization law,

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of stock solution = 0.12 M

[tex]V_1[/tex] = volume of stock solution = 20.0 ml

[tex]M_2[/tex] = molarity of diluted solution = ? M

[tex]V_2[/tex] = volume of diluted solution = 100.0 ml

Putting in the values we get:

[tex]0.12M\times 20.0=M_2\times 100.0[/tex]

[tex]M_2=0.024[/tex]

Therefore, the concentration of the resulting solution is 0.024 M.

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